My question, is this simplistic approach acceptable or are there any fallacies in it. Our maximum loading at each point is 5tons for the design. Therefore Ultimate shear load or Breaking Load = 30.9 x. ![]() In this case Ultimate shear strength = 0.6 x 51.5 = 30.9 kgs/mmsq. ![]() 785 x45 x45 = 1589.6 mmsqĪS the loading is in transverse direction and not the longitudinal ( along the length of the bar), I factor the breaking load by 0.6. Tensile strength of 304 SS = 505 MPa =51.5 kgs/mmsq (approx)Ĭross section area of round bar. Working Load Limit = Minimum Breaking Load / Safety Factor. I have used for my back of envelope, the following method : This is not my area of expertise and I seek your help. I have been asked to indicate WLL at each of the lifting point. The exposed length of rod is 200 mm, under which a 6ton belt can pass. There are 2 lifting points with 45mm dia 600mm long 304 grade S.S rod. ![]() I am planning to cast a 10 ton test weight ( 3000mmlong x 1160mm wide x 418mm high).
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